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SOLUTIONS/ANSWERS:
Solutions of Question no.1 of Depreciation
1 | |||||||
---|---|---|---|---|---|---|---|
Case | Purchase Price of Machinery | Installation Charges | Estimated Scrap Value | Estimated Useful Life (in Years) | Total Cost of Asset | Amount of Annual Depreciation | Rate of Depreciation |
a | b | c | d | e = a+b | f = e - c / d | g = f x 100 / e | |
a | 180000 | 20000 | 10000 | 5 | 200000 | 38000 | 19 |
b | 475000 | 25000 | 50000 | 5 | 500000 | 90000 | 18 |
c | 90000 | 10000 | 20000 | 10 | 100000 | 8000 | 8 |
d | 340000 | 60000 | 40000 | 10 | 400000 | 36000 | 9 |
e | 90000 | 10000 | 20000 | 4 | 100000 | 20000 | 20 |
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3
Amount Spend on Purchase of Second-Hand Machinery = 96000 + 24000 = 120000 ₹
Estimated Residual Value = 72000 ₹
= 120000 – 72000 = 48000
Annual Depreciation: Total Cost – Resideul Value / No. of Useful life of Machinery
= 120000 – 72000 / 4
Rate of Depreciation = Annual Depreciation x 100 / Total of Cost
=12000*100/120000
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